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シーソルト&ペーパー(Sea Salt & Paper)の報告
#74202: "Please randomize cards for shark draws"
rejected: 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています
1
どういった内容ですか?
どうしましたか?以下から選んでください
提案:次項がゲームを大きく改善すると思われる
詳細
• 何を意味するのか、簡単に理解できるようにあなたの提案を正確かつ簡潔に説明してください。
When player A plays a SHARK + SWIMMER combo, player B's cards should be randomized for the draw. It makes no sense for the cards to be sorted by type: no real-life player would keep all his mermaids on the right side and all his sharks on the left for the other player to pick exactly what they need. Yet when I steal from my opponent and I know they have a shark/swimmer, I click on their left-most card (as I see them) and voila! I have their shark/swimmer in my hand. Mermaids and other "points-only" cards (penguins, shells, lighthouse etc.) will be toward the right. People who know this have an advantage over newer players and it makes the game unfair.• あなたのブラウザは何ですか?
Mozilla v5
報告履歴
2022年10月21日 0:15 • thoun • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
It is random, in fact the card you click is never sent to the server ;) you can check the code if you doubt, you're not the first
2022年11月 2日 4:39 • OutOfHabit • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
Why do we even have have to select a card? I get selecting a player, but should not have to pick a card.
And should be automatic for 2-player games
And should be automatic for 2-player games
2022年11月12日 13:58 • This1KidTaylor • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
I noticed my most powerful cards are getting stolen more often than others so the players at my table tested and it seems true. The game automatically sorts the highest value cards to the top of your hand so anytime your opponents steal, all they have to do is steal the first card in the stack to get your best card.
I noticed my most powerful cards are getting stolen more often than others so the players at my table tested and it seems true. The game automatically sorts the highest value cards to the top of your hand so anytime your opponents steal, all they have to do is steal the first card in the stack to get your best card.
2022年11月28日 19:36 • applegummy • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
I agree with this report, when I click on the right most card of the other players hand and I know they have a mermaid, I have noticed I will likely get a mermaid and vice versa. Please look into this even if this shouldn't be the case as it's getting replicated
2022年12月14日 16:20 • Lou_00 • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
I agree, I am experiencing exactly the same issue. If I know that my adv. has a mermaid, I need to clic on the right card of his hands to be sure I'm stealing the mermaid.
2022年12月30日 20:01 • ccllaauuddiiaa • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
I agree with the other players, I recognized this as well, especially in tournament
2023年 1月 5日 21:52 • Otithes • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
It is NOT random. Mermaids tend to be on the right; the first card taken by the opponent tends to be on the left; random picks tend to give you whatever card the other player took last; and so on. I don’t know how it works, but experienced players are exploiting this and it breaks the game.
2023年 1月 5日 21:55 • thoun • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
Please check the code source, or simply the request sent to the server, if you don't trust my answer
2023年 1月 5日 22:52 • thoun • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
Here is an image of the network call you'll see when you steal, if you open F12 to network tab. As you can see, only the player id is sent, no cardId or card order. Do the test yourself if you don't trust me, or check the source code on my github (github.com/thoun)
imgur.com/a/Xg9J3Vi
imgur.com/a/Xg9J3Vi
2023年 1月19日 19:32 • Pricantora • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
Stealing should be of a random card after choosing the player you want to steal from. Don't let us choose a card!! My opponent can tell the order of my cards, therefore, it does not mimic the real game.
2023年 9月 4日 22:31 • silkkii • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
I checked the source code, relevant line here:
$card = $cardsInHand[bga_rand(1, $cardsNumber) - 1];
Isn't the function bga_rand(min, max) and card numbers go from 0 onwards? by starting from card number 1, it would always omit first card in that players hand, no?
So in case player you steal from has 2 cards, it would always pick the second card no matter what, unless I'm missing something here (like first card being special or card numbers starting from 1 instead of 0 - but then that -1 would omit the last card on that players hand instead).
$card = $cardsInHand[bga_rand(1, $cardsNumber) - 1];
Isn't the function bga_rand(min, max) and card numbers go from 0 onwards? by starting from card number 1, it would always omit first card in that players hand, no?
So in case player you steal from has 2 cards, it would always pick the second card no matter what, unless I'm missing something here (like first card being special or card numbers starting from 1 instead of 0 - but then that -1 would omit the last card on that players hand instead).
2023年 9月 4日 22:34 • thoun • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
There is a - 1 after bga_rand, so same result as writing $cardsInHand[bga_rand(0, $cardsNumber - 1)];
2023年 9月 4日 22:41 • silkkii • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
ah, that's correct, nevermind me then :D
2023年 9月 4日 22:49 • thoun • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
I made the same mistake the first time I checked my code after this bug report :) I don't remember why I wrote it this way, but it's still correct.
2024年 5月27日 18:06 • magroco • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
Everytime my mermaid got stolen, so there is no fun to play it when you know you lost your powerful cards that easy
2024年 7月31日 22:24 • nenptuk9Jtr • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
Shuffling the cards visually with a quick animation would help the non-technical people understand the concept of RNG a bit better.
Speaking about server-side and client-side calls would only help a fraction of a percent of the people who feel the need to open threads such as this one.
Speaking about random numbers will not help the people who insist on using www.dictionary.com/browse/anecdata to discuss the general behavior of a program.
Speaking about server-side and client-side calls would only help a fraction of a percent of the people who feel the need to open threads such as this one.
Speaking about random numbers will not help the people who insist on using www.dictionary.com/browse/anecdata to discuss the general behavior of a program.
2024年12月 3日 16:32 • Rebexus • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
Even if it is random how does the mermaid get picked much more often than any other card?
2025年 3月13日 17:40 • blockmonoid • 開発者はそれは良い考えではない、あるいは費用対効果が低すぎると考えています:
Seriously. I have mermaids stolen from my hand over 50% of the time. And this happens regularly out of a hand of 5+ cards. It does not seem random to me.
I'm looking at the code quoted above:
$card = $cardsInHand[bga_rand(1, $cardsNumber) - 1];
I understand the discussion above about the card numbering starting at 0 and why the -1 makes 0 possible. I see a potential bug with the max, however. If I have 2 cards in my hand, what is the value of $cardsNumber? Is it 2 or 1? If the value is 2, then everything works as it should. But if the value is 1 (because the programmer who wrote $cardsNumber was taking into account that the card numbering starts at 0), then your $card code would always produce 0 for a 2 card hand. That would explain why mermaids got selected more often.
I'm looking at the code quoted above:
$card = $cardsInHand[bga_rand(1, $cardsNumber) - 1];
I understand the discussion above about the card numbering starting at 0 and why the -1 makes 0 possible. I see a potential bug with the max, however. If I have 2 cards in my hand, what is the value of $cardsNumber? Is it 2 or 1? If the value is 2, then everything works as it should. But if the value is 1 (because the programmer who wrote $cardsNumber was taking into account that the card numbering starts at 0), then your $card code would always produce 0 for a 2 card hand. That would explain why mermaids got selected more often.
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