#18199: "Swiss tournament pairing improvement: color selection (hive, chess)"
どうしましたか?以下から選んでください
どうしましたか?以下から選んでください
同一内容の報告がないか、ご確認ください
もしそうなら、このレポートに投票してください。投票の多いレポートから調査されます!
# | Status | Votes | Game | Type | Title | Last update |
---|
詳細
• もしあれば、画面に表示されたエラーメッセージをコピー&ペーストしてください
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 何をしたいか、何をしたか、何が起きたかを説明してください
• あなたのブラウザは何ですか?
Google Chrome v81
• あなたの言語の代わりに、表示されている英語の文章をコピー&ペーストしてください。 もしこのバグのスクリーンショットがあれば(素晴らしい!)、Imgur.com等を使ってアップロードし、リンクをコピー&ペーストしてください。
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• このテキストは翻訳ページで翻訳可能になっていますか?もしそうならば、24時間以上前に翻訳されていますか?
• あなたのブラウザは何ですか?
Google Chrome v81
• 何を意味するのか、簡単に理解できるようにあなたの提案を正確かつ簡潔に説明してください。
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• あなたのブラウザは何ですか?
Google Chrome v81
• ブロックされたときの表示は何でしたか(空のスクリーン?一部のみのゲームインターフェイス?エラーメッセージ?)
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• あなたのブラウザは何ですか?
Google Chrome v81
• BGAで正しく実装されていないルールはどの部分ですか?
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• ルールの間違いはゲームのリプレイで確認できますか?そうであれば、行動番号は何番ですか?
• あなたのブラウザは何ですか?
Google Chrome v81
• やりたかったゲームアクションは何ですか?
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• このゲームアクションを引き起こす為に何を試みましたか?
• これを行おうとしたときに何が起こりましたか?(エラーメッセージ、ステータスバーメッセージ、他)
• あなたのブラウザは何ですか?
Google Chrome v81
• どの段階でこの問題が起こりましたか?(画面の指示はどうなっていましたか)
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• ゲームアクションを行おうとしたとき、何が起こりましたか?(エラーメッセージ、ステータスバーメッセージ、他)
• あなたのブラウザは何ですか?
Google Chrome v81
• 表示の問題を説明してください もしこのバグのスクリーンショットがあれば(素晴らしい!)、Imgur.com等を使ってアップロードし、リンクをコピー&ペーストしてください。
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• あなたのブラウザは何ですか?
Google Chrome v81
• あなたの言語の代わりに、表示されている英語の文章をコピー&ペーストしてください。 もしこのバグのスクリーンショットがあれば(素晴らしい!)、Imgur.com等を使ってアップロードし、リンクをコピー&ペーストしてください。
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• このテキストは翻訳ページで翻訳可能になっていますか?もしそうならば、24時間以上前に翻訳されていますか?
• あなたのブラウザは何ですか?
Google Chrome v81
• 何を意味するのか、簡単に理解できるようにあなたの提案を正確かつ簡潔に説明してください。
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• あなたのブラウザは何ですか?
Google Chrome v81
報告履歴
boardgamearena.com/tournament?id=38119
For example, in this tournament Frasco has all 4 games as white and pcapella has all 4 games black boardgamearena.com/tournament?id=106569
boardgamearena.com/bug?id=32483
boardgamearena.com/bug?id=32713
boardgamearena.com/bug?id=72619
報告に書き加える
- 他のテーブルID/行動ID
- F5キー(ページの再読込)で問題は解決されましたか?
- 問題は何回も起こりましたか?毎回 起こりますか?ランダムに起きますか?
- もしこのバグのスクリーンショットがあれば(素晴らしい!)、Imgur.com等を使ってアップロードし、リンクをコピー&ペーストしてください。